Decrease and Increment one month from the today date
Example1
$time = strtotime("2010-12-11");
echo date("Y-m-d", strtotime("-1 months",$time ));
Example2
$date = date("Y-m-d");// current date
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 day");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +2 week");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +1 month");
$date = strtotime(date("Y-m-d", strtotime($date)) . " +30 days");
Subtracting days from a date
The following example will
subtract 3 days from 1998-08-14. The result will be 1998-08-11.
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| $date = "1998-08-14";
$newdate = strtotime ( '-3 day' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
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Subtracting Weeks from a date
The following example will
subtract 3 weeks from 1998-08-14. The result will be 1998-07-24. Notice that the only difference in the code is the
week statement.
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| $date = "1998-08-14";
$newdate = strtotime ( '-3 week' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
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Subtracting Months from a date
The following example will
subtract 3 months from 1998-08-14. The result will be 1998-05-14. Notice that the only difference in the code is the
month statement.
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| $date = "1998-08-14";
$newdate = strtotime ( '-3 month' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
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Subtracting Years from a date
The following example will
subtract 3 years from 1998-08-14. The result will be 1995-08-14. Notice that the only difference in the code is the
year statement.
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| $date = "1998-08-14";
$newdate = strtotime ( '-3 year' , strtotime ( $date ) ) ;
$newdate = date ( 'Y-m-j' , $newdate );
echo $newdate;
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Adding days, months, weeks and years from a date
There
isn’t really much difference from subtracting and adding dates. To add
dates, just use any of the examples above and replace the negative (-)
with a positive (+) e.g. ‘+3 weeks’
